For an ideal gas undergoing a reversible

CHEMISTRY · Multi-part · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

For an ideal gas undergoing a reversible, isothermal process, the entropy change can be expressed in terms of either volume or pressure. Consider a sample of ideal gas that is initially at pressure P1P_1 and volume V1V_1 and undergoes a reversible, isothermal expansion to pressure P2P_2 and volume V2V_2 at temperature TT. (a) Starting from the ideal‐gas law and the definition of entropy, derive an expression for the molar entropy change, ΔSˉ\Delta \bar S, in terms of the initial and final pressures, P1P_1 and P2P_2, only. (b) Show algebraically that the expression you derived in part (a) is equivalent to the more familiar form that contains ln⁡(V2V1)\ln \left(\dfrac{V_2}{V_1}\right). Clearly state the mathematical step that makes the two forms identical. (c) Liquid nitrogen is vaporized and warmed to 300 K, forming 0.800 mol of gaseous N2_2 at 1.00 atm that then undergoes a reversible, isothermal compression to 5.00 atm. Using the expression you derived in part (a), calculate the entropy change of the nitrogen gas during the compression. (d) Discuss qualitatively whether your numerical answer in part (c) would change if the same compression were performed irreversibly but with the same initial and final states. Support your discussion with thermodynamic reasoning.

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