AD is an altitude of an isosceles triangle ABC in which

MATHEMATICS · Multi-part · CBSE · Mathematics · Triangles · Triangles

Problem

2. AD is an altitude of an isosceles triangle ABC in which AB=AC\mathrm{AB}=\mathrm{AC}. Show that (i) AD bisects BC (ii) AD bisects ∠A\angle \mathrm{A}.

Related theory

Browse the problem library