Oil drains from a storage tank according to

MATHEMATICS · Single correct · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

Oil drains from a storage tank according to V(t)=2000−50t2V(t) = 2000 - 50t^{2}, where V(t)V(t) is the volume (in gallons) remaining tt hours after a valve is opened. Determine when the oil is leaving the tank at a rate of 600 gal/h600\,\text{gal/h} and describe how that rate is changing at that instant. (a) At t≈5.3 ht \approx 5.3\,\text{h}, the oil is leaving at 600 gal/h600\,\text{gal/h} and the drain rate is becoming faster because V′′(5.3)=−100 gal/h2V''(5.3) = -100\,\text{gal/h}^2. (b) At t=12 ht = 12\,\text{h}, the oil is leaving at 600 gal/h600\,\text{gal/h} and the drain rate is becoming faster because V′′(12)=−50 gal/h2V''(12) = -50\,\text{gal/h}^2. (c) At t=6 ht = 6\,\text{h}, the oil is leaving at 600 gal/h600\,\text{gal/h} and the drain rate is becoming faster because V′′(6)=−100 gal/h2V''(6) = -100\,\text{gal/h}^2. (d) At t=6 ht = 6\,\text{h}, the oil is leaving at 600 gal/h600\,\text{gal/h} and the drain rate is becoming slower because V′′(6)=+100 gal/h2V''(6) = +100\,\text{gal/h}^2.

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