Starting at time from the origin with speed

MATHEMATICS · Single correct · AP · Calculus BC · Parametric, Polar, and Vector-Valued Functions · Parametric, Polar, and Vector-Valued Functions

Problem

Starting at time t=0t = 0 from the origin with speed 1 ms−11 \text{ ms}^{-1} , a particle follows a two-dimensional trajectory in the xx - yy plane so that its coordinates are related by the equation y=x22y = \frac{x^2}{2} . The xx and yy components of its acceleration are denoted by axa_x and aya_y , respectively. Then (1) ax=1 ms−2a_x = 1 \text{ ms}^{-2} implies that when the particle is at the origin, ay=1 ms−2a_y = 1 \text{ ms}^{-2} (2) ax=0a_x = 0 implies ay=1 ms−2a_y = 1 \text{ ms}^{-2} at all times (3) at t=0t = 0 , the particle's velocity points in the xx -direction (4) ax=0a_x = 0 implies that at t=1t = 1 s, the angle between the particle's velocity and the xx axis is 45∘45^\circ

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