If the capacitance of a nanocapacitor is measured in terms of a unit 'u' made by…

PHYSICS · Single correct · A Level · Physics · Measurements and their errors · Measurements and their errors

Problem

If the capacitance of a nanocapacitor is measured in terms of a unit 'u' made by combining the electric charge 'e', Bohr radius 'a₀', Planck's constant 'h' and speed of light 'c' then: (1)

u = \frac{e^2h}{a_0}

(2)

u = \frac{hc}{e^2a_0}

(3)

u = \frac{e^2c}{ha_0}

(4)

u = \frac{e^2a_0}{hc}

Related theory

Dimensions of Physical Quantities
Dimensional Analysis
Dimensional formulae

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