The endpoints of a diameter of a circle are and

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

The endpoints of a diameter of a circle are (32,−1)\left(\dfrac{3}{2},-1\right) and (−12,5)\left(-\dfrac{1}{2},5\right). Which of the following is the equation of the circle in general form with integer coefficients? (a) 4x2+4y2+4x+16y−23=04x^{2}+4y^{2}+4x+16y-23=0 (b) x2+y2−x−4y−234=0x^{2}+y^{2}-x-4y-\dfrac{23}{4}=0 (c) 4x2+4y2−4x−16y−23=04x^{2}+4y^{2}-4x-16y-23=0 (d) 4x2+4y2−4x−16y−143=04x^{2}+4y^{2}-4x-16y-143=0

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