An ideal battery is connected across nodes (positive) and (negative) of the network…

PHYSICS · Subjective · CBSE · Physics · Current Electricity · Current Electricity

Problem

An ideal 12 V12\,\text{V} battery is connected across nodes AA (positive) and BB (negative) of the network described below: • From AA to node CC there is a 4 Ω4\,\Omega resistor. • From CC to BB there is a 6 Ω6\,\Omega resistor. • A single 10 Ω10\,\Omega resistor connects AA directly to BB. • A 8 Ω8\,\Omega resistor joins node CC to node BB. The arrangement therefore contains two distinct closed paths sharing some elements. (i) Write two independent algebraic equations relating the currents in the branches of the network. (ii) Solve the equations to find the current supplied by the battery and the current through the 10 Ω10\,\Omega resistor. (iii) Calculate the power dissipated in the 6 Ω6\,\Omega resistor.

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