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Problem The specific conductivity of a saturated solution of AgCl is 3.40 × 10 − 6 ohm − 1 cm − 1 3.40 \times 10^{-6}\text{ ohm}^{-1}\text{ cm}^{-1} 3.40 × 1 0 − 6 ohm − 1 cm − 1 25 ∘ C 25^\circ\text{C} 2 5 ∘ C λ Ag + ∘ = 62.3 ohm − 1 cm 2 mol − 1 \lambda^\circ_{\text{Ag}^+} = 62.3\text{ ohm}^{-1}\text{ cm}^2\text{ mol}^{-1} λ Ag + ∘ = 62.3 ohm − 1 cm 2 mol − 1 λ Cl − ∘ = 67.7 ohm − 1 cm 2 mol − 1 \lambda^\circ_{\text{Cl}^-} = 67.7\text{ ohm}^{-1}\text{ cm}^2\text{ mol}^{-1} λ Cl − ∘ = 67.7 ohm − 1 cm 2 mol − 1 25 ∘ C 25^\circ\text{C} 2 5 ∘ C 2.6 × 10 − 5 M 2.6 \times 10^{-5}\text{ M} 2.6 × 1 0 − 5 M 4.5 × 10 − 3 M 4.5 \times 10^{-3}\text{ M} 4.5 × 1 0 − 3 M 3.6 × 10 − 5 M 3.6 \times 10^{-5}\text{ M} 3.6 × 1 0 − 5 M 3.6 × 10 − 3 M 3.6 \times 10^{-3}\text{ M} 3.6 × 1 0 − 3 M Browse the problem library