Let be the solid obtained as follows

MATHEMATICS · Single correct · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

Let SS be the solid obtained as follows. • For 0≤x≤π40\le x\le\dfrac{\pi}{4}, the base region is bounded by y=cos⁡xy=\cos x (top) and y=sin⁡xy=\sin x (bottom). • For π4≤x≤π2\dfrac{\pi}{4}\le x\le\dfrac{\pi}{2}, the base region is bounded by y=sin⁡xy=\sin x (top) and y=0y=0 (bottom). Cross sections perpendicular to the xx-axis are rectangles. On 0≤x≤π40\le x\le\dfrac{\pi}{4} the rectangles are squares (height equals base width); on π4≤x≤π2\dfrac{\pi}{4}\le x\le\dfrac{\pi}{2} the rectangles have height twice the base width. Which of the following expressions equals the volume of SS? (a) ∫0π/4(cos⁡x−sin⁡x) dx+2∫π/4π/2(sin⁡x)2 dx\displaystyle \int_{0}^{\pi/4}(\cos x-\sin x)\,dx+2\int_{\pi/4}^{\pi/2}(\sin x)^{2}\,dx (b) ∫0π/2(cos⁡x−sin⁡x)2 dx\displaystyle \int_{0}^{\pi/2}(\cos x-\sin x)^{2}\,dx (c) ∫0π/4(cos⁡x−sin⁡x)2 dx+2∫π/4π/2(sin⁡x)2 dx\displaystyle \int_{0}^{\pi/4}(\cos x-\sin x)^{2}\,dx+2\int_{\pi/4}^{\pi/2}(\sin x)^{2}\,dx (d) ∫0π/4(cos⁡x−sin⁡x)2 dx+∫π/4π/2(sin⁡x)2 dx\displaystyle \int_{0}^{\pi/4}(\cos x-\sin x)^{2}\,dx+\int_{\pi/4}^{\pi/2}(\sin x)^{2}\,dx

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