Let be a continuous function that satisfies for all real and on

MATHEMATICS · Single correct · AP · Calculus AB · Integration and Accumulation of Change · Integration and Accumulation of Change

Problem

Let ff be a continuous function that satisfies f(−x)=f(x)f(-x)=f(x) for all real xx and f(x)≥0f(x)\ge 0 on [−a,a][-a,a]. Which statement best justifies why the area enclosed by the graph of y=f(x)y=f(x) and the xx-axis on [−a,a][-a,a] equals 2∫0af(x) dx2\displaystyle\int_{0}^{a} f(x)\,dx? (a) Because ff is continuous, its integral over any symmetric interval equals twice the average value of ff on [0,a][0,a], so the total area is 2∫0af(x) dx2\displaystyle\int_{0}^{a} f(x)\,dx.},{ (b) Because ff is even, the region on [−a,0][-a,0] is a mirror image of the region on [0,a][0,a] with identical area. (c) Because ff is even, every antiderivative of ff is also even; therefore the definite integral doubles when the limits are symmetric. (d) Because ff is odd, the integrals on [−a,0][-a,0] and [0,a][0,a] cancel, so you must take twice the positive part on [0,a][0,a] to obtain the total area.

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