A bijective function satisfies for every with some function

MATHEMATICS · Subjective · CBSE · Mathematics · Relations and Functions · Relations and Functions

Problem

A bijective function f:R→Rf:\mathbb R\to\mathbb R satisfies (g∘f)(x)=x(g\circ f)(x)=x for every x∈Rx\in\mathbb R with some function gg. Is this single condition sufficient to conclude that g=f−1g=f^{-1}? Give a brief reason.

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