Two identical metal plates are given positive charges and ( ) respectively

PHYSICS · Single correct · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance

Problem

Two identical metal plates are given positive charges

Q_1

and

Q_2

(

Q_2 < Q_1

) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance

C

, the potential difference between them is (1)

(Q_1+Q_2)/(2C)

(2)

(Q_1+Q_2)/C

(3)

(Q_1-Q_2)/C

(4)

(Q_1-Q_2)/(2C)