While setting up the integral for the moment of inertia of a uniform thin rod of…

PHYSICS · Single correct · A Level · Physics · Engineering physics · Engineering physics

Problem

While setting up the integral for the moment of inertia of a uniform thin rod of length LL and mass MM about an axis through one end and perpendicular to the rod, which expression correctly represents the mass element dmdm of a small segment of length dxdx located at a distance xx from that end? (a) dm=ML x dxdm = \dfrac{M}{L}\,x\,dx (b) dm=LM dxdm = \dfrac{L}{M}\,dx (c) dm=ML dxdm = \dfrac{M}{L}\,dx (d) dm=M dxdm = M\,dx

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