Let be defined by g(x)= cases 2x+3, & x 1, (x-1)^ 2 +5, & x>1

MATHEMATICS · Subjective · AP · AP Precalculus · Exponential and Logarithmic Functions · Exponential and Logarithmic Functions

Problem

Let g:R→Rg:\mathbb{R}\to\mathbb{R} be defined by g(x)={2x+3,x≤1,(x−1)2+5,x>1.g(x)=\begin{cases} 2x+3, & x\le 1,\\ (x-1)^{2}+5, & x>1. \end{cases} Is gg one-to-one on R\mathbb{R}? Give a brief reason.

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