Let the polar curve be

MATHEMATICS · Single correct · AP · Calculus BC · Parametric, Polar, and Vector-Valued Functions · Parametric, Polar, and Vector-Valued Functions

Problem

Let the polar curve be r=2+sin⁡θr=2+\sin\theta. Determine the equation of the tangent line in slope–intercept form at θ=π6\theta=\dfrac{\pi}{6}. (a) y=33 x+252y=3\sqrt{3}\,x+\dfrac{25}{2} (b) y=−33 x−252y=-3\sqrt{3}\,x-\dfrac{25}{2} (c) y=−33 x+252y=-3\sqrt{3}\,x+\dfrac{25}{2} (d) y=−33 x+252y=-\dfrac{\sqrt{3}}{3}\,x+\dfrac{25}{2}

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