CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

If y=xxxy=x^{x^x}, then dydx=\frac{dy}{dx}= (a) y[xxlog⁡(ex)⋅log⁡x+xx]y\left[x^x\log(ex)\cdot\log x+x^x\right] (b) y[xxlog⁡(ex)⋅log⁡x+x]y\left[x^x\log(ex)\cdot\log x+x\right] (c) y[xxlog⁡(ex)⋅log⁡x+xx−1]y\left[x^x\log(ex)\cdot\log x+x^{x-1}\right] (d) y[xxlog⁡ex⋅log⁡x+xx−1]y\left[x^x\log_e x\cdot\log x+x^{x-1}\right]

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