Determine the nature of the convergence of the series .

MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

Determine the nature of the convergence of the series ∑n=1∞(−1)n−13n+2n2\displaystyle \sum_{n=1}^{\infty} (-1)^{n-1}\frac{3n+2}{n^{2}}. (a) The series converges absolutely since the ratio test yields a limit of 34<1\tfrac34<1. (b) The series diverges because its terms do not approach 00. (c) The series converges conditionally; the alternating terms decrease to 00 but the series of absolute values diverges. (d) The series diverges because 3n+2n2∼3n\dfrac{3n+2}{n^{2}}\sim\dfrac{3}{n} and ∑3n\sum \dfrac{3}{n} diverges.

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