For a hydrogen-like ion

CHEMISTRY · Single correct · CBSE · Chemistry · Structure of Atom · Structure of Atom

Problem

For a hydrogen-like ion, the energy of the electron in the nth orbit is given by (a)

E_n=-\dfrac{13.6\,Z^2}{n}\,\text{eV}

(b)

E_n=-\dfrac{13.6\,Z^2}{n^2}\,\text{eV}

(c)

E_n=+\dfrac{13.6\,Z^2}{n^2}\,\text{eV}

(d)

E_n=-\dfrac{13.6\,Z}{n^2}\,\text{eV}