The net reaction of the disc on the block is

PHYSICS · Single correct · CBSE · Physics · Laws of Motion · Laws of Motion

Problem

The net reaction of the disc on the block is (1) 12mω2R(e2ωt−e−2ωt)j^+mgk^\frac{1}{2}m\omega^2 R(e^{2\omega t} - e^{-2\omega t})\hat{j} + mg\hat{k} (2) 12mω2R(eωt−e−ωt)j^+mgk^\frac{1}{2}m\omega^2 R(e^{\omega t} - e^{-\omega t})\hat{j} + mg\hat{k} (3) −mω2Rcos⁡ωtj^−mgk^-m\omega^2 R \cos \omega t \hat{j} - mg\hat{k} (4) mω2Rsin⁡ωtj^−mgk^m\omega^2 R \sin \omega t \hat{j} - mg\hat{k}

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