A ball is thrown vertically upward with an initial speed of u. Neglect air resistance.
(i) Replacing the constant acceleration a in the standard kinematic equations by −g, derive an expression for the vertical displacement y of the ball at any time t after projection.
(ii) Using your result from part (i), show that the maximum height H reached by the ball is given by H=2gu2.
(iii) Calculate the maximum height attained when u=30ms−1, taking g=9.8ms−2.