The total number of divisors of that are of the form

MATHEMATICS · Numerical · CBSE · Mathematics · A Square and A Cube · A Square and A Cube

Problem

The total number of divisors of N=25⋅34⋅510⋅76N=2^5\cdot3^4\cdot5^{10}\cdot7^6 that are of the form 4k+24k+2, where k≥1k\ge1, is equal to

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