If , where a_ ij = cases i+j,&i j ^2-2j,&i=j cases then is equal…

MATHEMATICS · Single correct · CBSE · Mathematics · Determinants · Determinants

Problem

A=[a_{ij}]_{2\times2}

, where

a_{ij}=\begin{cases}i+j,&i\ne j\\i^2-2j,&i=j\end{cases}

then

A^{-1}

is equal to: (a)

\frac{1}{9}\begin{bmatrix}0&3\\3&1\end{bmatrix}

(b)

\frac{1}{9}\begin{bmatrix}0&-3\\3&-1\end{bmatrix}

(c)

\frac{1}{9}\begin{bmatrix}0&-3\\-3&-1\end{bmatrix}

(d)

\frac{1}{3}\begin{bmatrix}0&3\\3&1\end{bmatrix}