Using mass ( )

PHYSICS · Single correct · CBSE · Physics · Units and Measurements · Units and Measurements

Problem

Using mass (mm), length (ll), time (tt), and current (AA) as fundamental quantities, the dimensions of permeability are: (1) [M−1LT−2A][M^{-1}LT^{-2}A] (2) [ML−2T−2A−1][ML^{-2}T^{-2}A^{-1}] (3) [MLT−2A−2][MLT^{-2}A^{-2}] (4) [MLT−1A−1][MLT^{-1}A^{-1}]

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