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Calculate the pH of a 0.25 M aqueous solution of hydrofluoric acid (HF) at 25 °C
CHEMISTRY · Subjective · CBSE · Chemistry · Equilibrium · Equilibrium
Problem
Calculate the pH of a 0.25 M aqueous solution of hydrofluoric acid (HF) at 25 °C. The acid dissociation constant for HF is
K
a
=
6.6
×
10
−
4
K_a = 6.6 \times 10^{-4}
K
a
=
6.6
×
1
0
−
4
.
Related theory
Equilibrium
PH and ionic product
Ionic Equilibrium and pH
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