The reaction (in ) is first order in with rate constant

CHEMISTRY · Single correct · CBSE · Chemistry · Chemical Kinetics · Chemical Kinetics

Problem

The reaction N2O5\mathrm{N_2O_5} (in CCl4\mathrm{CCl_4}) →2NO2+12O2\rightarrow 2\mathrm{NO_2}+\frac{1}{2}\mathrm{O_2} is first order in N2O5\mathrm{N_2O_5} with rate constant 6.2×10−4 s−16.2\times10^{-4}\text{ s}^{-1}. What is the rate of reaction when [N2O5]=1.25 mol L−1[\mathrm{N_2O_5}]=1.25\text{ mol L}^{-1}? (a) 7.75×10−4 mol L−1 s−17.75\times10^{-4}\text{ mol L}^{-1}\text{ s}^{-1} (b) 6.35×10−3 mol L−1 s−16.35\times10^{-3}\text{ mol L}^{-1}\text{ s}^{-1} (c) 5.15×10−5 mol L−1 s−15.15\times10^{-5}\text{ mol L}^{-1}\text{ s}^{-1} (d) 3.85×10−4 mol L−1 s−13.85\times10^{-4}\text{ mol L}^{-1}\text{ s}^{-1}

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