CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

If y=log⁡log⁡xy=\log\log x, then eydydx=e^y\frac{dy}{dx}= (a) 1xlog⁡x\frac{1}{x\log x} (b) 1x\frac{1}{x} (c) 1log⁡x\frac{1}{\log x} (d) eye^y

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