In finding the electric field using Gauss law the formula is applicable

PHYSICS · Single correct · A Level · Physics · Fields and their consequences · Fields and their consequences

Problem

In finding the electric field using Gauss law the formula ∣E⃗∣=qencϵ0∣A∣|\vec{E}| = \frac{q_{enc}}{\epsilon_0 |A|} is applicable. In the formula ϵ0\epsilon_0 is permittivity of free space, AA is the area of Gaussian surface and qencq_{enc} is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation? (1) Only when the Gaussian surface is an equipotential surface. (2) Only when the Gaussian surface is an equipotential surface and ∣E⃗∣|\vec{E}| is constant on the surface. (3) Only when ∣E⃗∣=|\vec{E}| = constant on the surface. (4) For any choice of Gaussian surface.

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