A fixed quantity of an ideal gas is taken from state to state along two different…

PHYSICS · Multi-part · A Level · Physics · Further mechanics and thermal physics · Further mechanics and thermal physics

Problem

A fixed quantity of an ideal gas is taken from state AA to state BB along two different paths described below. In both cases the initial state has pressure P1P_{1} and volume V1V_{1}, and the final state has pressure P2P_{2} and volume V2V_{2} where P2=12P1P_{2}=\tfrac12P_{1} and V2=2V1V_{2}=2V_{1}. (i) Path I is a direct isothermal expansion from AA to BB. Path II consists of an isobaric expansion from (P1,V1)(P_{1},V_{1}) to (P1,2V1)(P_{1},2V_{1}) followed by an isochoric cooling to (P2,2V1)(P_{2},2V_{1}). Draw the two paths on the same PP–VV diagram and label them clearly. (ii) Show that Path I satisfies the mathematical form PV=constantPV=\text{constant} and hence justify that it is isothermal. (iii) Using the ideal–gas equation, determine the temperature at state BB for each path in terms of the initial temperature T1T_{1}. (iv) Explain, without using numerical integration, which of the two paths involves greater work done by the gas and give a qualitative reason based on the shapes of the curves on the PP–VV plane.

Related theory

Browse the problem library