Find the point(s) on the circle at which the tangent is horizontal.

MATHEMATICS · Single correct · AP · Calculus AB · Differentiation: Composite, Implicit, and Inverse Functions · Differentiation: Composite, Implicit, and Inverse Functions

Problem

Find the point(s) on the circle x2+y2=25x^{2}+y^{2}=25 at which the tangent is horizontal. (a) (5,0)(5,0) and (−5,0)(-5,0) (b) (0,5)(0,5) and (0,−5)(0,-5) (c) (52,−52)\left(\dfrac{5}{\sqrt{2}},-\dfrac{5}{\sqrt{2}}\right) and (−52,52)\left(-\dfrac{5}{\sqrt{2}},\dfrac{5}{\sqrt{2}}\right) (d) (3,4)(3,4) and (−3,−4)(-3,-4)

Related theory

Browse the problem library