Cell E and Cell F are based on the reaction with

CHEMISTRY · Single correct · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

Cell E and Cell F are based on the reaction 2Ag+(aq)+Fe(s)→2Ag(s)+Fe2+(aq)\mathrm{2Ag^{+}(aq)+Fe(s)\rightarrow 2Ag(s)+Fe^{2+}(aq)} with E∘=1.24 VE^{\circ}=1.24\,\text{V}. Cell E: [Ag+]=0.010 M[\mathrm{Ag^{+}}]=0.010\,\text{M} and [Fe2+]=1.0 M[\mathrm{Fe^{2+}}]=1.0\,\text{M} Cell F: [Ag+]=1.0 M[\mathrm{Ag^{+}}]=1.0\,\text{M} and [Fe2+]=0.010 M[\mathrm{Fe^{2+}}]=0.010\,\text{M} At 298 K298\,\text{K}, which statement correctly identifies which cell’s instantaneous potential deviates more from E∘E^{\circ} and provides the primary reason? (a) Both cells deviate equally because the squared silver concentration balances the opposite concentration changes. (b) Cell E deviates more because its larger reaction quotient produces a greater opposing term in the Nernst equation. (c) Cell F deviates more because its reactant-favored (Q<1) conditions raise the cell potential above E∘E^{\circ} by a larger amount. (d) The deviation cannot be compared since the presence of solids prevents an exact value for the reaction quotient.

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