The overall reaction CH₃CHO(g) + I₂(g) → CH₃COI(g) + HI(g) is experimentally found to…

CHEMISTRY · Single correct · AP · Chemistry · Kinetics · Kinetics

Problem

The overall reaction CH₃CHO(g) + I₂(g) → CH₃COI(g) + HI(g) is experimentally found to follow the rate law rate=k[CH3CHO]\text{rate} = k[\mathrm{CH_3CHO}] I₂ does not appear in the rate law even though it is a reactant in the balanced equation. Which of the following best accounts for the absence of I₂ in the rate law? (a) I2\mathrm{I_2} is present in large excess, so its concentration remains effectively constant throughout the reaction. (b) I2\mathrm{I_2} forms an intermediate in a rapid equilibrium prior to the slow step, allowing its concentration to be expressed in terms of [CH3CHO][\mathrm{CH_3CHO}]. (c) I2\mathrm{I_2} participates only after the rate-determining step, so variations in its concentration do not influence the overall rate. (d) I2\mathrm{I_2} is regenerated in a later step of the mechanism and therefore cancels out of the rate law.

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