A parallel-plate capacitor is charged to a potential difference of and then…

PHYSICS · Subjective · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance

Problem

A 1.0 μF1.0\,\mu\text{F} parallel-plate capacitor is charged to a potential difference of 120 V120\,\text{V} and then disconnected from the battery, so the charge on the plates remains constant. A dielectric slab with dielectric constant κ=4.0\kappa = 4.0 is completely inserted between the plates without changing their separation or area. Determine the new potential difference across the plates after the dielectric is inserted.

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