If and are the eccentricities of the hyperbola and

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

If ee and e′e' are the eccentricities of the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 and x2b2−y2a2=1\frac{x^2}{b^2} - \frac{y^2}{a^2} = 1 , then the point (1e,1e′)\left(\frac{1}{e}, \frac{1}{e'}\right) lies on the circle (1) x2+y2=1x^2 + y^2 = 1 (2) x2+y2=2x^2 + y^2 = 2 (3) x2+y2=3x^2 + y^2 = 3 (4) x2+y2=4x^2 + y^2 = 4

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