Let and be continuous on the closed interval and differentiable on

MATHEMATICS · Multi-part · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

Let ff and gg be continuous on the closed interval [a,c][a,c] and differentiable on (a,c)(a,c). Suppose that • f(a)=g(a)f(a)=g(a), f(b)=g(b)f(b)=g(b), and f(c)=g(c)f(c)=g(c) for some numbers a<b<ca<b<c, and • f(x)≠g(x)f(x)\ne g(x) for all xx in the open intervals (a,b)(a,b) and (b,c)(b,c). Throughout this problem, interpret "the region between the graphs of ff and gg on [a,c][a,c]" as the finite planar region bounded only by the two graphs and the vertical lines x=ax=a and x=cx=c. (a) Explain why the region between the graphs of ff and gg on [a,c][a,c] can be decomposed into exactly two smaller regions, one lying entirely between x=ax=a and x=bx=b and the other lying entirely between x=bx=b and x=cx=c. Justify your answer without referencing any particular formulas for area. (b) Prove that the total area of the region described above is equal to ∫ac∣f(x)−g(x)∣ dx\displaystyle \int_a^{c} |f(x)-g(x)|\,dx. Your explanation must rely on properties of definite integrals and the fact that ∣u∣=±u|u|=\pm u according to the sign of uu. (c) Suppose instead that f(x)−g(x)f(x)-g(x) does not change sign on [a,c][a,c]. Describe how the integrand in part (b) simplifies and explain, in complete sentences, why this agrees with the usual "top minus bottom" formula many students memorize.

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