For , a particle is moving along a curve so that its position at time is . At time ,…

MATHEMATICS · Multi-part · AP · Calculus BC · Parametric, Polar, and Vector-Valued Functions · Parametric, Polar, and Vector-Valued Functions

Problem

For t≥0t \ge 0 , a particle is moving along a curve so that its position at time tt is (x(t),y(t))(x(t), y(t)) . At time t=2t = 2 , the particle is at position (1,5)(1, 5) . It is known that dxdt=t+2et\frac{dx}{dt} = \frac{\sqrt{t+2}}{e^t} and dydt=sin⁡2t\frac{dy}{dt} = \sin^2 t . (1) Is the horizontal movement of the particle to the left or to the right at time t=2t = 2 ? Explain your answer. Find the slope of the path of the particle at time t=2t = 2 . (2) Find the xx-coordinate of the particle's position at time t=4t = 4 . (3) Find the speed of the particle at time t=4t = 4 . Find the acceleration vector of the particle at time t=4t = 4 . (4) Find the distance traveled by the particle from time t=2t = 2 to t=4t = 4 .

Related theory

Browse the problem library