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Points lie on a circle with centre such that
MATHEMATICS · Single correct · CBSE · Mathematics · Circles · Circles
Problem
Points
A
,
B
,
C
A, B, C
A
,
B
,
C
lie on a circle with centre
O
O
O
such that
A
B
=
A
C
AB = AC
A
B
=
A
C
. The radius
A
O
AO
A
O
is produced to meet the circle again at
D
D
D
. If
∠
B
A
C
=
42
∘
\angle BAC = 42^{\circ}
∠
B
A
C
=
4
2
∘
, then
∠
A
D
C
\angle ADC
∠
A
D
C
equals (a)
90
∘
90^{\circ}
9
0
∘
(b)
48
∘
48^{\circ}
4
8
∘
(c)
69
∘
69^{\circ}
6
9
∘
(d)
96
∘
96^{\circ}
9
6
∘
Related theory
Properties of Triangles
Triangle Properties
Circles
Circle angle properties
Angle subtended by a chord
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