MATHEMATICS · Single correct · AP · Calculus AB · Limits and Continuity · Limits and Continuity
Problem
Consider p(x)=x−5∣x−5∣ and the values listed near x=5.
x : 5.1 5.01 5.001
p(x): 1 1 1
x : 4.9 4.99 4.999
p(x): –1 –1 –1
Find the right-hand limit x→5+limp(x).
(a) −1
(b) 0
(c) 1
(d) The limit does not exist