Find the percentage error in the specific resistance given by

PHYSICS · Subjective · CBSE · Physics · Units and Measurements · Units and Measurements

Problem

Find the percentage error in the specific resistance given by ρ=πr2Rl\rho=\dfrac{\pi r^2R}{l}, where the radius is r=(0.20±0.02) cmr=(0.20\pm0.02)\,\text{cm}, the resistance is R=(60±2) ΩR=(60\pm2)\,\Omega, and the length is l=(150±0.1) cml=(150\pm0.1)\,\text{cm}.

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