An ice cube of mass at is placed in an isolated container which is at

PHYSICS · Subjective · AP · Physics 2: Algebra-based · Thermodynamics · Thermodynamics

Problem

An ice cube of mass 0.1 kg0.1 \text{ kg} at 0∘C0^\circ\text{C} is placed in an isolated container which is at 227∘C227^\circ\text{C} . The specific heat SS of the container varies with temperature TT according to the empirical relation S=A+BTS = A + BT , where A=100 cal/kg-KA = 100 \text{ cal/kg-K} and B=2×10−2 cal/kg-K2B = 2 \times 10^{-2} \text{ cal/kg-K}^2 . If the final temperature of the container is 27∘C27^\circ\text{C} , determine the mass of the container. (Latent heat of fusion of water = 8×104 cal/kg8 \times 10^4 \text{ cal/kg} , Specific heat of water = 103 cal/kg-K10^3 \text{ cal/kg-K} ).

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