Earth’s mass is and its radius is

PHYSICS · Single correct · CBSE · Physics · Gravitation · Gravitation

Problem

Earth’s mass is 6.0×1024 kg6.0\times10^{24}\,\text{kg} and its radius is 6.4×106 m6.4\times10^{6}\,\text{m}. Calculate the escape velocity from the surface of a hypothetical planet that has the same radius as Earth but twice its mass. Take G=6.67×10−11 N m2 ⁣/ ⁣kg2G = 6.67\times10^{-11}\,\text{N\,m}^2\!/\!\text{kg}^2. (a) 1.1×104 m/s1.1\times10^{4}\,\text{m/s} (b) 2.2×104 m/s2.2\times10^{4}\,\text{m/s} (c) 1.6×104 m/s1.6\times10^{4}\,\text{m/s} (d) 7.9×103 m/s7.9\times10^{3}\,\text{m/s}

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