The position of a particle is

MATHEMATICS · Single correct · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

The position of a particle is s(t)=t3−6kt2+9k2ts(t)=t^{3}-6kt^{2}+9k^{2}t, where kk is a positive constant and tt is in seconds. The particle attains a local maximum position at t=2 st=2\text{ s}. What is the value of kk? (a) k=23k=\dfrac{2}{3} (b) k=1k=1 (c) k=2k=2 (d) k=4k=4

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