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Calculate the freezing point of an aqueous solution of non-electrolyte having an…
CHEMISTRY · Subjective · CBSE · Chemistry · Solutions · Solutions
Problem
Calculate the freezing point of an aqueous solution of non-electrolyte having an osmotic pressure 2.0 atm at 300 K.
K
f
=
1.86
K mol
−
1
kg
K_f = 1.86 \text{ K mol}^{-1} \text{ kg}
K
f
=
1.86
K mol
−
1
kg
and
S
=
0.0821
litre atm K
−
1
mol
−
1
S = 0.0821 \text{ litre atm K}^{-1} \text{ mol}^{-1}
S
=
0.0821
litre atm K
−
1
mol
−
1
. Assume molarity and molality same.
Related theory
Osmotic Pressure
Colligative Properties
Solutions
Depression in freezing point
Colligative Properties and Molar Mass
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