Consider a mine of depth drilled straight towards the centre of the Earth

PHYSICS · Multi-part · CBSE · Physics · Gravitation · Gravitation

Problem

Consider a mine of depth dd drilled straight towards the centre of the Earth. The Earth is assumed to have uniform density. (i) Using the idea that only the mass lying at a distance less than (R−d)(R-d) from the centre contributes to the gravitational force, derive an exact expression for the acceleration due to gravity gdg_d at depth dd below the surface. (ii) For d≪Rd \ll R, simplify the result obtained in part (i) to the linear form gd=g(1−dR)g_d = g\bigl(1-\frac{d}{R}\bigr). (iii) Show mathematically that g→0g \rightarrow 0 as d→Rd \rightarrow R and interpret the physical meaning of this result. (iv) Find the value of gd/gg_d/g when d=R2d = \tfrac{R}{2}. Comment on how rapidly gg falls with depth in comparison with altitude.

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