The function is defined on the closed interval by .

MATHEMATICS · Multi-part · AP · Calculus AB · Analytical Applications of Differentiation · Analytical Applications of Differentiation

Problem

The function hh is defined on the closed interval [0,2π][0,2\pi] by h(x)=2sin⁡2x−3xh(x)=2\sin^{2}x-3x. (a) Write an explicit formula for h′(x)h'(x). (b) Solve h′(x)=0h'(x)=0 for xx in the open interval (0,2π)(0,2\pi), giving exact values. (c) Determine all subintervals of (0,2π)(0,2\pi) on which hh is increasing and all subintervals on which hh is decreasing. Provide analytic justification. (d) Evaluate hh at the critical points found in part (b) and at the endpoints of the interval. Using these values together with your results from part (c), identify the absolute maximum and absolute minimum values of hh on [0,2π][0,2\pi], stating both the xx–coordinates and the corresponding function values. Explain your reasoning thoroughly.

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