The electrons of oxygen ( ) and fluorine ( ) are

CHEMISTRY · Subjective · AP · Chemistry · Atomic Structure and Properties · Atomic Structure and Properties

Problem

The 2p2p electrons of oxygen (Z=8Z = 8) and fluorine (Z=9Z = 9) are, on average, the same distance 3.5×10−11 m3.5 \times 10^{-11}\,\text{m} from the nucleus. Assuming the shielding experienced by these electrons is identical, calculate the ratio IE1(F)IE1(O)\dfrac{IE_{1}(\text{F})}{IE_{1}(\text{O})}.

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