The solution of the inequality is:

MATHEMATICS · Single correct · CBSE · Mathematics · Inverse Trigonometric Functions · Inverse Trigonometric Functions

Problem

The solution of the inequality (tan⁡−1x)2−3tan⁡−1x+2≥0(\tan^{-1}x)^2 - 3\tan^{-1}x + 2 \geq 0 is: (a) (−∞,tan⁡1]∪[tan⁡2,∞)(-\infty, \tan 1] \cup [\tan 2, \infty) (b) (−∞,tan⁡1](-\infty, \tan 1] (c) (−∞,−tan⁡1]∪[tan⁡2,∞)(-\infty, -\tan 1] \cup [\tan 2, \infty) (d) [tan⁡2,∞)[\tan 2, \infty)

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