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What is the concentration of in a solution prepared by dissolving 0.01 mole of in 1 L
CHEMISTRY · Subjective · CBSE · Chemistry · Equilibrium · Equilibrium
Problem
What is the concentration of
CH
3
COOH
(
aq
)
\text{CH}_3\text{COOH}(\text{aq})
CH
3
COOH
(
aq
)
in a solution prepared by dissolving 0.01 mole of
NH
4
+
CH
3
COO
−
\text{NH}_4^+\text{CH}_3\text{COO}^-
NH
4
+
CH
3
COO
−
in 1 L
H
2
O
\text{H}_2\text{O}
H
2
O
? Report your answer after multiplying by
9
×
10
5
9 \times 10^5
9
×
1
0
5
.
[
K
a
(
CH
3
COOH
)
=
1.8
×
10
−
5
,
K
b
(
NH
3
,
H
2
O
)
=
1.8
×
10
−
5
]
[K_a(\text{CH}_3\text{COOH}) = 1.8 \times 10^{-5}, K_b(\text{NH}_3, \text{H}_2\text{O}) = 1.8 \times 10^{-5}]
[
K
a
(
CH
3
COOH
)
=
1.8
×
1
0
−
5
,
K
b
(
NH
3
,
H
2
O
)
=
1.8
×
1
0
−
5
]
Related theory
Buffer Solutions
Equilibrium
Salt Hydrolysis
Ionic Equilibrium and pH
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