Charges and are fixed at points and separated by

PHYSICS · Single correct · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance

Problem

Charges +4 μC+4\,\mu\text{C} and +6 μC+6\,\mu\text{C} are fixed at points AA and BB separated by 0.20 m0.20\,\text{m}. A point PP is 0.12 m0.12\,\text{m} from AA and 0.16 m0.16\,\text{m} from BB. Taking k=9×109 N m2C−2k = 9\times10^{9}\,\text{N m}^2\text{C}^{-2}, calculate the electric potential at PP. (a) 9.0×105 V9.0\times10^{5}\,\text{V} (b) 3.0×105 V3.0\times10^{5}\,\text{V} (c) 6.4×105 V6.4\times10^{5}\,\text{V} (d) 7.5×105 V7.5\times10^{5}\,\text{V}

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