PHYSICS · Single correct · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance
Problem
Charges +4μC and +6μC are fixed at points A and B separated by 0.20m. A point P is 0.12m from A and 0.16m from B. Taking k=9×109N m2C−2, calculate the electric potential at P.
(a) 9.0×105V
(b) 3.0×105V
(c) 6.4×105V
(d) 7.5×105V