The base of a triangle is fixed and its vertex moves such that ( )

MATHEMATICS · Subjective · CBSE · Mathematics · Coordinate Geometry · Coordinate Geometry

Problem

The base ABAB of a triangle is fixed and its vertex CC moves such that sin⁡A=ksin⁡B\sin A = k \sin B ( k≠1k \neq 1 ). Show that the locus of CC is a circle whose centre lies on the line ABAB and whose radius is equal to ak(1−k2)\frac{ak}{(1-k^2)} , aa being the length of the base ABAB .

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