A particle moving along a line has acceleration given by meters per second squared for

MATHEMATICS · Multi-part · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

A particle moving along a line has acceleration given by a(t)=−9+3ta(t)=-9+3t meters per second squared for 0≤t≤60\le t\le 6. At time t=0t=0 seconds the particle’s velocity is 1212 meters per second and its position is 55 meters. (a) Determine explicit formulas for the velocity v(t)v(t) and the position s(t)s(t) of the particle for 0≤t≤60\le t\le 6. (b) Find the time tt at which the velocity attains an extreme value on the given interval. Classify this extreme value as a maximum or minimum and justify your answer. (c) Identify all intervals on 0<t<60<t<6 during which the particle is speeding up and all intervals during which it is slowing down. Explain how you used the relationship between vv and aa to reach your conclusions. (d) Determine the particle’s maximum displacement from its initial position during 0≤t≤60\le t\le 6. Support your answer with appropriate reasoning based on your expressions for ss, vv, and aa. State your result with units.

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